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6k^2-48k-54=0
a = 6; b = -48; c = -54;
Δ = b2-4ac
Δ = -482-4·6·(-54)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-60}{2*6}=\frac{-12}{12} =-1 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+60}{2*6}=\frac{108}{12} =9 $
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